Chapter 3: Analysis of Financial Statements
Chapter 4: Time Value of Money
Discussions Questions (DQs)
1. Do Problem 3-13 on pp. 113-114.
Chapter 4: Time Value of Money
Discussions Questions (DQs)
1. Do Problem 3-13 on pp. 113-114.
2. Do Thomson ONE Problem on p. 117.
3. Do Problems 4-1 thru 4-12 on pp. 165-166.
Problem Set 1
3-13: Data for Morton Chip Company and its
industry average
(a) Indicated ratios for Morton:
Ratio
Morton Industry Analysis
Current Assets/Current Liabilities 1.98 times 2.0
Days Sale Outstanding
76.29 days 35.0
days
Sales/Inventory
6.66 times 6.7
Sales/Fixed Assets
5.50 times 12.1
Sales/Total Assets 1.70 times 3.0
Net Income/Sales
1.7 % 1.2%
Net Income/Total Assets 2.9% 3.6%
Net Income/ Common Equity 7.6% 9.0%
Total Debt/ Total Assets
61.9% 60.0%
Working Note: The Calculation of above ratios
is shown below:
·
Current
Assets/Current Liabilities = $655,000 / $330,000 = 1.98 times
·
Days
Sale Outstanding = Receivables/ (Average Sales per Day) = (Receivables/Annual
Sales) 365 days= ($336,000 / $1,607,500) 365 days = 76.29 days
·
Sales/Inventory
= $1,607,500 / 241,500 = 6.66 times
·
Sales/Fixed
Assets = $1,607,500 / $ 2,92,500 = 5.50
times
·
Sales/Total
Assets = $1,607,500 / $ 947,500 = 1.70
times
·
Net
Income/Sales = $27,300 / $16,07,500 = 0.017 or 1.7%
·
Net
Income/Total Assets = $27,300 / $947,500 = 0.029 or 2.9%
·
Net
Income/ Common Equity = $27,300 /
$361,000 = 0.076 or 7.6%
·
Total
Debt/ Total Assets = ($330,000 + $256,500) / $947,500 = 0.619 or 61.9%
(b)
Calculation of Extended Du
Pont equation for both Morton and the industry
For Morton:
Return on
Common Equity (ROE)
= Return on Assets x Equity multiplier
= (Profit margin x Total assets
turnover) x (Equity multiplier)
= (Net Income / Sales) x (Sales /
Total Assets) x (Total Assets / Common Equity)
= 1.7% x 1.70 x ($947,500/$361,000)
= 7.6%
For Industry:
Return on Common Equity (ROE)
= Return on Assets x Equity multiplier
= (Profit margin x Total assets
turnover) x (Equity multiplier)
= (Net Income / Sales) x (Sales /
Total Assets) x (Total Assets / Common Equity)
= 1.2% x 3 x (Net Income / Common
Equity) ÷ (Net Income / Total Assets)
=1.2% x 3 x (9% ÷ 3.6%)
= 9%
(c)
Strength and Weakness of
Morton:
By comparing the Morton ratios with
the industry average ratios, we can find the following strengths and weaknesses:
·
Morton’s current ratio (1.98) is lesser than
the industry average (2) which shows that it is a good and Morton can pay its
short-term obligations at time.
·
Morton’s
Days Sales Outstanding (76.29 days) is higher than that of Industry average(35
days) so it is very poor indicating the weakness of Morton's collection of
account receivables.
·
Morton’s
Inventory turnover ratio is 6.66 which is equivalent to industry average (6.7).
It shows that quite satisfactory for Morton.
·
Morton’s
fixed asset ratios is 5.50 times which is very lower than industry average(12.1
times) so it indicates that Morton is not using its fixed asset properly.
·
Total
assets turnover ratio of Morton (1.7 times) is lesser than average industry (3 times)
so it is very poor as compared to industry which shows ineffective utilization
of the inventory and assets.
·
Profit
margin ratio of Morton (1.7%) is higher than industry average (1.2%) so that it
shows Morton’s prices are relatively high and costs are relatively low.
·
Morton’s return on assets is 2.9% which is
below the industry average (3.6%) so it shows that low earning power of Morton.
·
Morton’s
return on equity (7.6%) is below the industry average (9%) which shows the
weakness of Morton.
·
Morton’s
Debt ratio is 61.9% which is higher than average industry (60%) so that it is
comparatively satisfactory but not good, and borrowing additional fund should
be controlled.
(d) If Morton had doubled its
sales as well as its inventories, account receivables, and common equity during
2010 then it would have certainly affected the validity of ratio analysis. As a
result of that, it is likely to increase the Days sales outstanding, total
asset ratio, fixed asset ratio and decrease the return on equity, profit margin
on sales, and finally there wouldn’t be changed in inventory turnover ratio.
Apart from these ratios, no effect can be observed. Thus, financial decisions
based on these ratios are likely to be affected by these changes.
References
C.
Paramasivan, T. Subramanian. (2015). Financial Management. New Delhi:
New Age International Publishers.
Eugene F. Brigham, Michael C.
Ehrhardt. (2011). Financial Management: Theory and Practice . Natorp
Boulevard Mason, USA: South-Western Cengage Learning.
4- 1. Solution:
Here given,
Present Value (PV) =
$10,000
Interest rate (i)
= 10%
No. of years (n) =
5 years
Future Value (FV) = ?
We know that,
= 10,000 x
(1+0.1)5
=
$16,105.10
Therefore, the amount will be $16,105.10 after five years.
4- 2. Solution:
Here given,
Future Value (FV)
= $5,000
Interest rate (i)
=
7%
No. of years (n) =
20 years
Present Value (PV)
=?
We know that,
PV = FV x [1/ (1+i)] n
= $5,000 x (1/1.07)20
= $1292.095
Thus, the present value of a security is $1,292.1
4- 3. Solution:
Here given,
No of years (n) = 18 years
Present Value (PV) =
$250,000
Future Value (FV) = $1
million
Interest rate (i) =?
Here,
FV = PV x (1+i) n
$ 1,000,000 = $ 250,000
x (1+i) 18
(1+i) 18= 4
1+i= (4)1/18
i = 1.0801 -1
i= 0.0801
i =
8.01%
Thus, the annual interest rate should be of 8.01% p.a. to earn to reach
goal with no additional funds.
4- 4. Solution:
Let,
Present Value (PV) = y
Future value (FV) = 2y
Interest (i)
=
6.5% (Given)
No of years
(n) = ?
As we know,
FV =
PV x (1+i) n
2y/y = (1+6.5%) n
2 = (1.065) n
Taking log on both sides,
Log (2) = log (1.065) n
Log
(2) = n log (1.065)
n = log (2)/log (1.065)
n = log (2)/log (1.065)
n = 11.0067
Therefore, it will take approximately 11 years to double the amount
deposited at the interest of 6.5%.
4- 5. Solution:
Here given,
Present Value (PV) =
$42,108.53
Payment
(PMT) =
$5,000
Interest rate (i)
= 12%
Future value (FV) =
$250,000
No. of years (n)
=?
Here,
FV= PMT/i x [(1+i) n -1)] + PV x (1 + i) n
$250,000 = $5000/0.12 x
[(1+0.12) n-1] + $42,180.53(1+0.12) n
(1.12) n = 3.4786
(1.12) n = 3.4786
Taking log on both sides,
n log 1.12 = log 3.4786
n = 11.0041years
Thus, it will take approx.11 years to reach the goal of $250,000.
4- 6. Solution:
Here given,
Interest rate (i)
= 7%
No. of years (n)
= 5 years
Payment
(PMT) = $300 each year
Future Value (FVA) of an annuity =?
Here,
FVA
n = PMT/i x [(1+I) n – 1]
FVA5 = $300/0.07 x [(1.07)5- 1]
= $1725.2217
Therefore, the future value will be $1725.22.
If this were annuity due, the future valued would be,
FVA due=PMT/I [(1+i)n-1] x (1+i)
=
$300/0.07[(1+0.07)5-1] x (1+0.07)
= $ 1845.9872
4- 7. Solution:
Here given,
Interest Rate (i) = 8%
Time period (n) = 6
years
Where,
Present Value Interest Factor (PVIF) = 1/ (1+r)
t
Present Value = Cash Flow x PVIF
End of year (t)
|
Cash Flow
|
PVIF at 8%
|
Present Value = Cash flow X PVIF
|
1
|
$100
|
0.9259
|
$92.59
|
2
|
$100
|
0.8573
|
$85.73
|
3
|
$100
|
0.7938
|
$79.38
|
4
|
$200
|
0.7350
|
$147.00
|
5
|
$300
|
0.6805
|
$204.15
|
6
|
$500
|
0.6301
|
$315.05
|
Total Present Value
|
=$ 923.90
|
Now,
FV =
PV (1+i) n
= $923.90(1+0.08)6
= $1466.1131
4- 8. Solution:
Given,
Present Value (PV) = $20,000,
Time (n) (12 x 5) = 60
months,
Interest per month =
12/12 = 1%,
Future Value (FV) =
0
Payment (PMT) = ?
EFF = ?
We know that,
PMT = PV (1+r) n [r /
[(1+r) n-1}]
= $20,000 (1+0.01) 60 x 0.01 / [(1+0.01) 60-1]
= $444.9
And,
Compounding period (m) =
12 months
Monthly interest rate
= 1%
Here,
EFF = (1+Periodic Rate) Compounding
period -1
EEF = (1+i/m) m-1
= (1+0.01)12-1
=12.68%
4-9 (a) Solution:
Given,
Present Value (PV) =
$500
Time (n)
=1 year
Interest rate (i) = 6%
Future Value (FV) =?
Here,
FV = PV (1 + i) n
=
$500(1+0.06)1
= $530
Using calculator:
PV = -$500
n=1 i/Y=6 CPT and FV =
$530
Thus, the deposit will be $530 at the end of a year.
4-9 (b) Solution:
Given,
Present Value (PV) = $500
Time
(n) =2
year
Interest rate (i) =
6%
Future
Value (FV) =?
Here,
FV = PV (1 +i) n
= $500(1+.06)2
=$561.80
Using calculator:
PV = -$500 n=2 i/Y=6 CPT
and FV = $561.8
Thus, the deposit will be $561.8 at the end of 2 years.
4-9 (c) Solution:
Given,
Future Value (FV) = $500
Time
(n)
=1 year
Interest rate (i)
=
6%
Present Value (PV) = ?
Here,
PV =
FV/ (1+i) n
PV =
$500/ (1+0.06)1
= $471.7
Using calculator:
FV = $500 n=1 i/Y =
6 CPT and PV = -$471.6981
Therefore, $471.7 is needed as of today to receive $500 after 1 year at
6% discount rate.
4-9 (d) Solution:
Given,
Future Value (FV) = $500
Time (n)
=2
year
Interest rate (i) = 6%
Present Value (PV) =?
Here,
PV = FV/ (1+i) n
PV =
$500/ (1+0.06)2
= $445.0
Using calculator:
FV = $500 n=1 i/Y =
6 CPT and PV = -$444.9982
Therefore, a deposit of $444.9982 is needed as of today to receive $500
after 2 years at 6% discount rate.
4-10 (a) Solution:
Given,
Present
(PV) =
$500
Time
(n)
=10
years
Interest (i)
= 6%
Future Value (FV) =?
Here,
FV =
PV (1 +i) n
FV =
$500(1+.06)10
= $895.4238
Using calculator:
PV = -$500 n=10 i/Y=6 CPT and FV =
$895.4238
Thus, the deposit will be $895.4238 at the end of 10 year
4-10 (b) Solution:
Given,
Present Value (PV) = $500
Time
(n)
=10
years
Interest rate (i) = 12%
Future Value (FV) = ?
Here,
FV =
PV (1 +i)n
FV =
$500(1+.12)10
= $1552.92
Using calculator:
PV = -$500 n=10 i/Y=12 CPT
and FV = $1552.9241
Thus, the deposit will be $1552.92 at the end of 10 year
4-10 (c) Solution:
Given,
Future Value (FV) = $500
Time
(n)
=10
year
Interest rate (i)
=
6%
Present Value (PV) = ?
Here,
PV = FV/(1+i)n
PV =$500/(1+0.06)
10
= $279.20
Using calculator:
FV = $500 n=10 i/Y =
6 CPT and PV = -$279.1974
Thus, deposit of $279.20 is needed as of today to receive $500 after 10
years at 6% discount rate.
4-10 (d) Solution:
Given,
Future Value (FV) = $500
Time
(n)
=10
year
Interest rate (i)
= 12%
Present Value (PV) = ?
Here,
PV =
FV/(1+i)n
PV =
$500/(1+0.12)10
= $160.99
Using calculator:
FV = $500 n=10 I/Y = 12
CPT and PV = -$160.9866
Thus, the deposit of $160.99 is needed as of today to receive $500 after
10 years at 12% discount rate.
4-11 Solution:
Given,
Present Value (PV) = $200
Future Value (FV) = 2 x 200
= $400
Time
(n) =
?
Here,
FV =PV
(1+i) n
(1+i) n = FV/PV
4-11 (a) Solution:
Here, Interest rate (i) = 7%
(1+i) n = FV/PV
1.07n = 400 /
200
1.07n = 2
Taking log both sides,
log1.07n= log2
n = log2 / log1.07
n = 10.25
n = 10 years
Thus, it will take 10 years for $200 to double if it deposited at 7% interest
rate.
4-11 (b) Solution:
Here, interest rate (i)
= 10%
n= log2/log1.1
n = 7.27 years
Thus, it will take 7.27 years for $200 to double if it deposited at 10%
interest rate.
4-11 (c). Solution:
Here, interest rate (i) = 18%
n= log2/log1.18
n =
4.18 years
Thus, it will take 4.18 years for $200 to double if it deposited at 18%
interest rate.
4-11 (d). Solution:
i = 100%
n =
log2/ log2
n = 1 year
Thus, it will take 1 year for $200 to double if it deposited at 100%
interest rate.
4- 12(a) Solution:
Given,
Payment (PMT) = $400
Time (n) = 10 years
Interest rate (i) = 10%
Future Value (FV) = ?
Here,
FV = PMT x [(1+i) n – 1] /
i
Using Calculator:
PMT = -$400 PV = 0
n = 10 I/Y = 10 CPT
and Press FV
FV = $6374.9698
4- 12(b) Solution:
Given,
Payment (PMT) = $200
Time (n) = 5 years
Interest rate (i) = 5%
Future Value (FV) = ?
FV = PMT x [(1+i) n – 1] / i
Using calculator:
PMT = -$200 PV = 0
n = 5 i/Y = 5 CPT
and Press FV
FV = $1105.1263
4-12 (c) Solution:
Given,
Payment (PMT) = $400
Time (n) = 5 years
Interest rate (i) = 0%
Future Value (FV) = ?
FV = PMT x [(1+i) n – 1] / i
Using calculator:
PMT = -$400 PV = 0 n = 5
i/Y = 0 CPT and Press FV
FV = $2000
4-12 (d) solution:
Re-calculating on part a, b and c by assuming as an annuity due is as
follows:
First of all changing the setting of the calculator for calculating annuities
due
2nd PMT > 2nd Enter
> 2nd CPT (Settings Changed for Annuity)
a)
PMT =
-$400, PV = 0, n = 10, I/Y = 10, CPT and Press FV
FV = $7012.4668
b)
PMT =
-$200, PV = 0, n = 5, I/Y = 5, CPT and Press FV
FV = $1160.3826
c)
PMT =
-$400, PV = 0, n = 5, I/Y = 0, CPT and Press FV
FV = $2000
References
C.
Paramasivan, T. Subramanian. (2015). Financial Management. New Delhi:
New Age International Publishers.
Eugene F. Brigham, Michael C. Ehrhardt. (2011). Financial
Management: Theory and Practice . Natorp Boulevard Mason, USA:
South-Western Cengage Learning.
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